0.25x^2+2x+4=4

Solution for 0.25x^2+2x+4=4 equation:

0.25x^2+2x+4=4

We move all terms to the left:

0.25x^2+2x+4-(4)=0

We add all the numbers together, and all the variables

0.25x^2+2x=0

a = 0.25; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·0.25·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*0.25}=\frac{-4}{0.5}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*0.25}=\frac{0}{0.5}
=0
$